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2x-x^2/100=99
We move all terms to the left:
2x-x^2/100-(99)=0
We multiply all the terms by the denominator
-x^2+2x*100-99*100=0
We add all the numbers together, and all the variables
-1x^2+2x*100-9900=0
Wy multiply elements
-1x^2+200x-9900=0
a = -1; b = 200; c = -9900;
Δ = b2-4ac
Δ = 2002-4·(-1)·(-9900)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-20}{2*-1}=\frac{-220}{-2} =+110 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+20}{2*-1}=\frac{-180}{-2} =+90 $
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